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JEE-Main_2024
30.01.24_(S1)
Question
The electric field of an electromagnetic wave in free space is represented as $\vec{E}=E_0 \cos (\omega t-k z) \hat{\imath}$. The corresponding magnetic induction vector will be :
Select the correct option:
A
$\vec{B}=E_0 C \cos (\omega t-k z) \hat{\jmath}$
B
$\vec{B}=\frac{E_0}{c} \cos (\omega t-k z) \hat{\jmath}$
C
$\vec{B}=E_0 \operatorname{Cos}(\omega t+k z) \hat{\jmath}$
D
$\vec{B}=\frac{E_0}{c} \cos (\omega t+k z) \hat{\jmath}$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
$\begin{aligned} & \text { Given } \vec{E}=E_0 \cos (\omega t-k z) \hat{\imath} \\ & \vec{B}=\frac{E_0}{C} \cos (\omega t-k z) \hat{\jmath} \\ & \hat{C}=\hat{E} \times \hat{B}\end{aligned}$
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