Two Conducting Circular Loops A...... | JEE Main 2024

JEE MAIN 2024

05-04-24 S1

Question

Two conducting circular loops A and B are placed in the same plane with their centres coinciding as shown in figure. The mutual inductance between them is:

Select the correct option:

$\frac{\mu_0 \pi a^2}{2 b}$

$\frac{\mu_0}{2 \pi} \cdot \frac{b^2}{a}$

$\frac{\mu_0 \pi b^2}{2 a}$

$\frac{\mu_0}{2 \pi} \cdot \frac{a^2}{b}$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

$\begin{aligned} & \phi=\mathrm{Mi}=\mathrm{BA} \\ & \Rightarrow \mathrm{Mi}=\frac{\mu_0 \mathrm{i}}{2 \mathrm{~b}} \pi \mathrm{a}^2 \\ & \therefore \mathrm{M}=\frac{\mu_0 \pi \mathrm{a}^2}{2 \mathrm{~b}}\end{aligned}$

Question Tags

JEE Main

Physics

Medium

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