The kinetic energy of an... | JEE Main 2023 | Modern Physics

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JEE MAIN 2023

06-04-23 S1

Question

The kinetic energy of an electron, $\alpha$-particle and a proton are given as 4K, 2K and K respectively. The de-Broglie wavelength associated with electron ( $\lambda \mathrm{e}$ ) $\alpha$-particle ( $\lambda \alpha$ ) and the proton ( $\lambda \mathrm{p}$ ) are as follows .

Select the correct option:

A

$\lambda \alpha=\lambda \mathrm{p}<\lambda \mathrm{e}$

B

$\lambda \alpha>\lambda \mathrm{p}>\lambda \mathrm{e}$

C

$\lambda \alpha<\lambda \mathrm{p}<\lambda \mathrm{e}$

D

$\lambda \alpha=\lambda \mathrm{p}>\lambda \mathrm{e}$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

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