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JEE MAIN_2025
030425_S2
Question
A particle is projected with velocity $u$ so that its horizontal range is three times the maximum height attained by it. The horizontal range of the projectile is given as $\frac{m u^2}{25 g}$, where value of n is: (Given, ' g ' is the acceleration due to gravity.)
Select the correct option:
A
12
B
18
C
24
D
6
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
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Question Tags
JEE Main
Physics
Medium
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