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JEE MAIN 2025
07.04.25 S2
Question
Match List - I with List - II.
List - I
(A) Solution of chloroform and acetone
(B) Solution of ethanol and water
(C) Solution of benzene and toluene
(D) Solution of acetic acid in benzene
List - II
(I) Minimum boiling azeotrope
(II) Dimerizes
(III) Maximum boiling azeotrope
(IV) $\Delta \mathrm{V}_{\text {mix }}=0$
Choose the correct answer from the options given below:
Select the correct option:
A
(A)-(III), (B)-(I), (C)-(IV), (D)-(II)
B
(A)-(II), (B)-(I), (C)-(IV), (D)-(III)
C
(A)-(III), (B)-(IV), (C)-(I), (D)-(II)
D
(A)-(II), (B)-(IV), (C)-(I), (D)-(III)
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
Sol. (A) Solution of chloroform and acetone shows -ve deviation, so maximum boiling azeotrope.
(B) Solution of ethanol \& water shows + ve deviation. So minimum boiling azeotrope.
(C) Solution of benzene and toluene form ideal solution. $\Delta \mathrm{V}_{\text {mix }}=0$.
(D) Acetic acid in benzene form dimer.|
Question Tags
JEE Main
Chemistry
Easy
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