Energy density associated|Electromagnetic Waves|JEEMAIN-2023

JEE MAIN 2023

06-04-23 S2

Question

The energy density associated with electric field $E$ and magnetic field $B$ of an electromagnetic wave in free space is given by ( $\epsilon_0$ - permittivity of free space, $\mu_0$ - permeability of free space)

Select the correct option:

$U_E=\frac{E^2}{2 \epsilon_0}, U_B=\frac{B^2}{2 \mu_0}$

$U_E=\frac{E^2}{2 \epsilon_0}, U_B=\frac{\mu_0 B^2}{2}$

$U_E=\frac{\epsilon_0 E^2}{2}, U_B=\frac{\mu_0 B^2}{2}$

$U_E=\frac{\epsilon_0 E^2}{2}, U_B=\frac{B^2}{2 \mu_0}$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Question Tags

JEE Main

Physics

Easy

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