Wheatstone bridge principle is used to measure the specific resistance $\left(S_1\right)$ of given wire, having length L , radius r . If X is the resistance of wire, then specific resistance is: $\mathrm{S}_1=\mathrm{X}\left(\frac{\pi \mathrm{r}^2}{\mathrm{~L}}\right)$. If the length of the wire gets doubled then the value of specific resistance will be
Select the correct option:
A
$\frac{S_1}{4}$
B
$2 \mathrm{~S}_1$
C
$\frac{S_1}{2}$
D
$S_1$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
As specific resistance does not depends on dimension of wire so, it will not change.
Hello 👋 Welcome to Competishun – India’s most trusted platform for JEE & NEET preparation. Need help with JEE / NEET courses, fees, batches, test series or free study material? Chat with us now 👇
