Production of iron in blast furnace follows the following equation
$\mathrm{Fe}_3 \mathrm{O}_4(\mathrm{~s})+4 \mathrm{CO}(\mathrm{g}) \rightarrow 3 \mathrm{Fe}(\mathrm{l})+4 \mathrm{CO}_2(\mathrm{~g})$
when 4.640 kg of Fe3O4 and 2.520 kg of CO are allowed to react then the amount of iron (in g) produced is :
Given : Molar Atomic mass (g mol -1): $\mathrm{Fe}=56$
Molar Atomic mass $\left(\mathrm{g} \mathrm{mol}^{-1}\right): 0=16$
Molar Atomic mass $\left(\mathrm{g} \mathrm{mol}^{-1}\right):=\mathrm{C}=12$