1 L aqueous solution of $\mathrm{H}_2 \mathrm{SO}_4$ contains $0.02 \mathrm{~m} \mathrm{~mol} \mathrm{H}_2 \mathrm{SO}_4 .50 \%$ of this solution is diluted with deionized water to give 1 L solution (A). In solution (A), 0.01 m mol of $\mathrm{H}_2 \mathrm{SO}_4$ are added. Total m mols of $\mathrm{H}_2 \mathrm{SO}_4$ in the final solution is $\_\_\_\_$ $\times 10^3 \mathrm{~m}$ mols.