Let the abscissae of the two points $P$ and $Q$ be the roots of $2 x^2-r x+p=0$ and the ordinates of $P$ and $Q$ be the roots of $x^2-s x-q=0$. If the equation of the circle described on $P Q$ as diameter is $2\left(x^2+y^2\right)-11 x-14 y-22=$ 0 , then $2 r+s-2 q+p$ is equal to
