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JEE MAIN 2022
28-06-2022
Question
A ball is spun with angular acceleration $\alpha=6 t^2-2 t$ where $t$ is in second and $\alpha$ is in rads-2. At $t=0$, the ball has angular velocity of $10 \mathrm{rads}^{-1}$ and angular position of 4 rad . The most appropriate expression for the angular position of the ball is:
Select the correct option:
A
$\frac{3}{2} t^4-t^2+10 t$
B
$\frac{t^4}{2}-\frac{t^3}{3}+10 t+4$
C
$\frac{2 t^4}{3}-\frac{t^3}{6}+10 t+12$
D
$2 t^4-\frac{t^3}{2}+5 t+4$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
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Question Tags
JEE Main
Physics
Medium
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