A mass of 10 kg is suspended vertically by a rope of length 5m from the roof. A force of 30 N is applied at the middle point of rope in horizontal direction. The angle made by upper half of the rope with vertical is $\theta=\tan ^{-1}\left(x \times 10^{-1}\right)$. The value of $x$ is $\_\_\_\_$ (Given $\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^2$ )
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$\begin{aligned} & \mathrm{T} \sin \theta=30 \\ & \mathrm{~T} \cos \theta=100 \\ & \Rightarrow \tan \theta=0.3\end{aligned}$