Report Issue

JEE MAIN 2022
27-6-2022 S2
Question
If $y(x)=\left(x^{x^x}\right), x>0$ then $\frac{d^2 x}{d y^2}+20$ at $x=1$ is equal to :
Write Your Answer
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
Solution Image
Question Tags
JEE Main
Mathematics
Hard
Start Preparing for JEE with Competishun