Energy density u = (α/β) sin(αx/k... | JEE Main 2022

JEE MAIN 2022

27-07-2022 - S2

Question

An expression of energy density is given by $\mathrm{u}=\frac{\alpha}{\beta} \sin \left(\frac{\alpha \mathrm{x}}{\mathrm{kt}}\right)$ , where $\alpha, \beta$ are constants, x is displacement, k is Boltzmann constant and t is the temperature. The dimensions of $\beta$ will be :

Select the correct option:

$\left[\mathrm{ML}^2 \mathrm{~T}^{-2} \theta^{-1}\right]$

$\left[\mathrm{M}^0 \mathrm{~L}^2 \mathrm{~T}^{-2}\right]$

$\left[\mathrm{M}^0 \mathrm{~L}^0 \mathrm{~T}^0\right]$

$\left[\mathrm{M}^0 \mathrm{~L}^2 \mathrm{~T}^0\right]$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution