A student in the laboratory measures... | Units & Measurements

JEE MAIN 2022

28-06-22 (S2)

Question

A student in the laboratory measures thickness of a wire using screw gauge. The readings are 1.22 mm , $1.23 \mathrm{~mm}, 1.19 \mathrm{~mm}$ and 1.20 mm . The percentage error is $\frac{\mathrm{x}}{121} \%$. The value of x is

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

$\begin{aligned} & X=\frac{1.22 \mathrm{~mm}+1.23 \mathrm{~mm}+1.19 \mathrm{~mm}+1.20 \mathrm{~mm}}{4} \\ & X=1.21 \mathrm{~mm} \\ & \Delta X=\frac{0.01+0.02+0.02+0.01}{4}=\frac{0.06}{4}=0.015 \\ & \text { Percentage error }=\frac{0.015}{1.21} \times 100 \\ & X=150\end{aligned}$

Question Tags

JEE Main

Physics

Easy

Start Preparing for JEE with Competishun

Report Issue