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JEE MAIN 2021
26-06-2021 S1
Question
The maximum value of the term independent of ' t ' in the expansion of $\left(t^{\frac{1}{5}}+\frac{(1-x)^{\frac{1}{10}}}{t}\right)^{10}$ where $x \in (0,1)$ is
Select the correct option:
A
$\frac{10!}{\sqrt{3}(5!)^2}$
B
$\frac{2.10!}{3 \sqrt{3}(5!)^2}$
C
$\frac{2.10!}{3(5!)^2}$
D
$\frac{10!}{3(5!)^2}$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
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Mathematics
Medium
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