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JEE-MAIN 2021
17-03-2021 S2
Question
The electric field intensity produced by the radiation coming from a 100 W bulb at a distance of 3 m is E. The electric field intensity produced by the radiation coming from 60 W at the same distance is $\sqrt{\frac{x}{5} \mathrm{E}}$ Where the value of $x=$
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Question Tags
JEE Main
Physics
Easy
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