A Parallel Plate Capacitor.... | JEE Main 2021 | Capacitance

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JEE-MAIN 2021

26-08-2021 S2

Question

A parallel - plate capacitor with plate area $A$ has separation $d$ between the plates. Two dielectric slabs of dielectric constant $K_1$ and $K_2$ of same area $A / 2$ and thickness $d / 2$ are inserted in the space between the plates. The capacitance of the capacitor will be given by :

Select the correct option:

A

$\frac{\varepsilon_0 A}{d}\left(\frac{1}{2}+\frac{K_1 K_2}{K_1+K_2}\right)$

B

$\frac{\varepsilon_0 A}{d}\left(\frac{1}{2}+\frac{K_1 K_2}{2\left(K_1+K_2\right)}\right)$q

C

$\frac{\varepsilon_0 A}{d}\left(\frac{1}{2}+\frac{K_1+K_2}{K_1 K_2}\right)$

D

$\frac{\varepsilon_0 A}{d}\left(\frac{1}{2}+\frac{2\left(K_1+K_2\right)}{K_1 K_2}\right)$

✓ Correct! Well done.

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