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JEE MAIN 2021
1-9-21 S2
Question
If the conductivity of mercury at $0^{\circ} \mathrm{C}$ is $1.07 \times 10^6 \mathrm{~S} \mathrm{~m}^{-1}$ and the resistance of a cell containing mercury is $0.243 \Omega$, then the cell constant of the cell is $\mathrm{x} \times 104 \mathrm{~m}-1$. The value of x is $\_\_\_\_$ (Nearest integer)
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Solution
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Question Tags
JEE Main
Chemistry
Easy
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