Let us consider a curve|Differential Equations|JEEMAIN 2021

JEE MAIN 2021

27-08-2021 S1

Question

Let us consider a curve, $y=f(x)$ passing through the point $(-2,2)$ and the slope of the tangent to the curve at any point ( $x, f(x)$ ) is given by $f(x)+x f^{\prime}(x)=x^2$. |Then :

Select the correct option:

$x^2+2 x f(x)-12=0$

$x^3-3 x f(x)-4=0$

$x^3+3 x f(x)-4=0$

$x^2+2 x f(x)+4=0$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Question Tags

JEE Main

Mathematics

Easy

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