TD_JEE MAIN_09-04-2019_S2 - Competishun – Live JEE & NEET Courses and Exam Prep

JEE MAIN 2019

09-04-2019 S2

Question

Let P be the plane, which contains the line of intersection of the planes, x + y + z – 6 = 0 and 2x + 3y + z + 5 = 0 and it is perpendicular to the xy-plane. Then the distance of the point (0, 0, 256) from P is equal to :

Select the correct option:

$63 \sqrt{5}$

$\frac{17}{\sqrt{5}}$

$205 \sqrt{5}$

$\frac{11}{\sqrt{5}}$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Question Tags

JEE Main

Mathematics

Medium

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