6.023 × 10²² molecules are present in 10 g... | Some Basic Concepts

JEE-MAIN 2020

03-09-2020 S2

Question

$6.023 \times 10^{22}$ molecules are present in 10 g of a substance ' x '. The molarity of a solution containing 5 g of substance ' x ' in 2 L solution is $\_\_\_\_$ $\times 10^{-3} \mathrm{~mol} \mathrm{lt}^{-1}$

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JEE Main

Chemistry

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