The position co-ordinates of a particle moving in a 3-D coordinate system is given by x = a cos ωt, y = a sin ωt, and z = aωt
The speed of the particle is:
Select the correct option:
A
$2 \mathrm{a} \omega$
B
$\sqrt{2} \mathrm{a} \omega$
C
$\sqrt{3} \mathrm{a} \omega$
D
$\mathrm{a} \omega$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
$\begin{aligned} & v_x=-a \omega \sin \omega t \\ & v_y=a \omega \cos \omega t \\ & v_z=a \omega \\ & v=\sqrt{v_x^2+v_y^2+v_z^2}=\sqrt{2} a \omega\end{aligned}$
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