If a curve $\mathrm{y}=f(\mathrm{x})$, passing through the point $(1,2)$, is the solution of the differential equation, $2 \mathrm{x}^2 \mathrm{dy}=\left(2 \mathrm{xy}+\mathrm{y}^2\right) \mathrm{dx}$, then $\mathrm{f}\left(\frac{1}{2}\right)$ is equal to:
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