Quadratic Equation_ JEE MAIN_2019_10-04-2019-S-1 - Competishun

JEE MAIN_2019_

10-04-2019-S-1

Question

If $\alpha$ and $\beta$ are the roots of the quadratic equation, $x^2+x \sin \theta-2 \sin \theta=0, \quad \theta \in\left(0, \frac{\pi}{2}\right)$, then $\frac{\alpha^{12}+\beta^{12}}{\left(a^{-12}+\beta^{-12}\right) \cdot(\alpha-\beta)^{24}}$ is equal to :

Select the correct option:

$\frac{2^{12}}{(\sin \theta-8)^5}$

$\frac{2^{12}}{(\sin \theta-4)^{12}}$

$\frac{2^6}{(\sin \theta+8)^{12}}$

$\frac{2^{12}}{(\sin \theta+8)^{12}}$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution