7.9 MeV α-particle scatters... |JEE Main 2026 22 Jan Shift 1

JEE MAIN 2026

22-01-2026 S1

Question

$7.9 \mathrm{MeV} \alpha$-particle scatters from a target material of atomic number 79 . From the given data the estimated diameter of nuclei of the target material is (approximately) $\_\_\_\_$ m. $\left[\frac{1}{4 \pi \epsilon_0}=9 \times 10^9 \mathrm{Nm}^2 / \mathrm{C}^2\right.$ and electron charge $\left.=1.6 \times 10^{-19} \mathrm{C}\right]$

Select the correct option:

$5.76 \times 10^{-14}$

$1.44 \times 10^{-13}$

$2.88 \times 10^{-14}$

$1.69 \times 10^{-12}$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution