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JEE Advanced 2024
Paper-1 2024
Question
Consider the ellipse $\frac{x^2}{9}+\frac{y^2}{4}=1$. Let $S(p, q)$ be a point in the first quadrant such that $\frac{p^2}{9}+\frac{q^2}{4}>1$. Two tangents are drawn from $S$ to the ellipse, of which one meets the ellipse at one end point of the minor axis and the other meets the ellipse at a point $T$ in the fourth quadrant. Let $R$ be the vertex of the ellipse with positive $x$-coordinate and $O$ be the center of the ellipse. If the area of the triangle $\triangle O R T$ is $\frac{3}{2}$, then which of the following options is correct?
Select the correct option:
A
$q=2, p=3 \sqrt{3}$
B
$q=2, p=4 \sqrt{3}$
C
$q=1, p=5 \sqrt{3}$
D
$q=1, p=6 \sqrt{3}$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
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Question Tags
JEE Advance
Mathematics
Medium
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