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JEE Advance 2008
paper 1
Question
Consider the system of equations $$ \begin{aligned} & x-2 y+3 z=-1 \\ & -x+y-2 z=k \\ & x-3 y+4 z=1 \end{aligned} $$ STATEMENT -1 : The system of equations has no solution for $\mathrm{k} \neq 3$. and STATEMENT -2 : The determinant $\left|\begin{array}{ccc}1 & 3 & -1 \\ -1 & -2 & \mathrm{k} \\ 1 & 4 & 1\end{array}\right| \neq 0$, for $\mathrm{k} \neq 3$.
Select the correct option:
A
Statement-1 is True, Statement-2 is True; Statement-2 is a correct explanation for Statement-1
B
Statement -1 is True, Statement-2 is True; Statement-2 is NOT a correct explanation for Statement-1
C
Statement -1 is True, Statement -2 is False
D
Statement - 1 is False, Statement - 2 is True
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
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JEE Advance
Mathematics
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