Let a line passing through the point $(-1,2,3)$ intersect the lines $\mathrm{L}_1: \frac{\mathrm{x}-1}{3}=\frac{\mathrm{y}-2}{2}=\frac{\mathrm{z}+1}{-2}$ at $M(\alpha, \beta, \gamma)$ and $L_2: \frac{x+2}{-3}=\frac{y-2}{-2}=\frac{z-1}{4}$ at $N(a, b, \mathrm{c})$. Then the value of $\frac{(\alpha+\beta+\gamma)^2}{(a+b+c)^2}$ equals