A block of mass 5 kg starting from rest pulled up on a smooth incline plane making an angle of $30^{\circ}$ with horizontal with an affective acceleration of $1 \mathrm{~ms}^{-2}$. The power delivered by the pulling force at $\mathrm{t}=10 \mathrm{~s}$ from the start is $\_\_\_\_$ W. [Use $\mathrm{g}=10 \mathrm{~ms}^{-2}$ ] (calculate the nearest integer value)
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Solution
Sol.
$$
\begin{aligned}
& F-5 g \sin 30^{\circ}=5 a \Rightarrow F=5+25=30 \mathrm{~N} \\
& V_{10}=u+a t \Rightarrow v_{10}=0+1(10)=10 \mathrm{~m} / \mathrm{s} \\
& P_{10}=F v=300 \mathrm{~W}
\end{aligned}
$$
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