A cylinder is rolling down on an inclined plane of inclination $60^{\circ}$. It's acceleration during rolling down will be $\frac{\mathrm{x}}{\sqrt{3}} \mathrm{~m} / \mathrm{s}^2$, where $\mathrm{x}=$ $\_\_\_\_$ (use $\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^2$ ).
