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JEE MAIN 2020

05-09-2020 S1

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A force $\vec{F}=(\hat{i}+2 \hat{j}+3 \hat{k}) \mathrm{N}$ acts at a point $(4 \hat{i}+3 \hat{j}+\hat{k}) \mathrm{m}$. Then the magnitude of torque about the point $(\hat{i}+2 \hat{j}+\hat{k}) m$ will be $\sqrt{x} N-m$. The value of $x$ is $\_\_\_\_$ .

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