A galvanometer having a resistance of $20 \Omega$ and 30 divisions on both sides has figure of merit 0.005 ampere/division. The resistance that should be connected in series such that it can be used as a voltmeter upto 15 volt, is:
Select the correct option:
A
100$\Omega$
B
125$\Omega$
C
80$\Omega$
D
120$\Omega$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
Full scale deflection current, Ig = 30 × 0.005 = 0.15 A
15 = (20 + R) × 0.15
⇒ R = 80 Ω
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