A particle moves from the point (2i+4j)... | Relative Motion

JEE MAIN 2019

11-01-2019 S2

Question

A particle moves from the point $(2.0 \mathrm{i}+4.0 \mathrm{j}) \mathrm{m}$, at $\mathrm{t}=0$, with an initial velocity $(5.0 \mathrm{i}+4.0 \mathrm{j}) \mathrm{ms}^{-1}$. It is acted upon by a constant force which produces a constant acceleration $(4.0 \hat{\mathrm{i}}+4.0 \hat{\mathrm{j}}) \mathrm{ms}^{-2}$. What is the distance of the particle from the origin at time 2 s ?

Select the correct option:

$20 \sqrt{2} \mathrm{~m}$

15 m

$10 \sqrt{2} \mathrm{~m}$

5 m

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution