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JEE MAIN 2019
09-04-2019 S2
Question
A particle ' P ' is formed due to a completely inelastic collision of particles ' x ' and ' y ' having de-Broglie wavelengths ' $\lambda_{\mathrm{x}}$ ' and ' $\lambda_{\mathrm{y}}$ ' respectively. If x and y were moving in opposite directions, then the de-Broglie wavelength of ' P ' is
Select the correct option:
A
$\frac{\lambda_x \lambda_y}{\left|\lambda_x-\lambda_y\right|}$
B
$\lambda_{\mathrm{x}}-\lambda_{\mathrm{y}}$
C
$\lambda_x+\lambda_y$
D
$\frac{\lambda_x \lambda_y}{\lambda_x+\lambda_y}$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
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Physics
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