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JEE MAIN 2025
04-04-2025 SHIFT-1
Question
A small mirror of mass m is suspended by a massless thread of length $l$ . Then the small angle through which the thread will be deflected when a short pulse of laser of energy E falls normal on the mirror (c = speed of light in vacuum and g = acceleration due to gravity)
Select the correct option:
A
$\theta = \frac{E}{{mc\sqrt {gl} }}$
B
$\theta = \frac{{2E}}{{mc\sqrt {gl} }}$
C
$\theta = \frac{E}{{2mc\sqrt {gl} }}$
D
$\theta = \frac{{3E}}{{4mc\sqrt {gl} }}$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
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JEE Main
Physics
Hard
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