A square $A B C D$ has all its vertices on the curve $x^2 y^2=1$. The midpoints of its sides also lie on the same curve. Then, the square of area of $A B C D$ is
Hello 👋 Welcome to Competishun – India’s most trusted platform for JEE & NEET preparation. Need help with JEE / NEET courses, fees, batches, test series or free study material? Chat with us now 👇