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JEE MAIN 2019
08-04-2019 S1
Question
A steel wire having a radius of 2.0 mm , carrying a load of 4 kg , is hanging from a ceiling. Given that g $=3.1 \pi \mathrm{~ms}-2$, what will be the tensile stress that would be developed in the wire?
Select the correct option:
A
$4.8 \times 10^6 \mathrm{Nm}^{-2}$
B
$3.1 \times 10^6 \mathrm{Nm}^{-2}$
C
$5.2 \times 10^6 \mathrm{Nm}^{-2}$
D
$6.2 \times 10^6 \mathrm{Nm}^{-2}$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
Stress $=\frac{F}{A}=\frac{4 \times 3.1 \pi}{\pi \times\left(2 \times 10^{-3}\right)^2}=3.1 \times 10^6 \mathrm{~N} / \mathrm{m}^2$
Question Tags
JEE Main
Physics
Easy
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