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JEE MAIN_2019_
S2_100419
Question
A uniformly charged ring of radius 3a and total charge q is placed in xy-plane centred at origin. A point charge q is moving towards the ring along the z-axis and has speed v at z = 4a. The minimum value of v such that it crosses the origin is:
Select the correct option:
A
$\sqrt{\frac{2}{m}}\left(\frac{1}{15} \frac{q^2}{4 \pi \varepsilon_0 a}\right)^{1 / 2}$
B
$\sqrt{\frac{2}{m}}\left(\frac{1}{5} \frac{q^2}{4 \pi \varepsilon_0 a}\right)^{1 / 2}$
C
$\sqrt{\frac{2}{m}}\left(\frac{4}{15} \frac{q^2}{4 \pi \varepsilon_0 a}\right)^{1 / 2}$
D
$\sqrt{\frac{2}{m}}\left(\frac{2}{15} \frac{q^2}{4 \pi \varepsilon_0 a}\right)^{1 / 2}$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
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JEE Main
Physics
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