As shown in the figure, a plane mirror is fixed at a height of 50 cm from the bottom of tank containing water $\left(\mu=\frac{4}{3}\right)$. The height of water in the tank is 8 cm . A small bulb is placed at the bottom of the water tank. The distance of image of the bulb formed by mirror from the bottom of the tank is $\_\_\_\_$ cm.
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Solution
Apparent depth of $O=\frac{d}{\mu}=6$
Distance between O and $\mathrm{I}_2=48+50=98 \mathrm{~cm}$
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Apparent depth of $O=\frac{d}{\mu}=6$
Distance between O and $\mathrm{I}_2=48+50=98 \mathrm{~cm}$