Let $f: R \rightarrow R$ satisfy the equation $f(x+y)=f(x)$. $f(y)$ for all $x, y \in R$ and $f(x) \neq 0$ for any $x \in R$. If Ihe function f is differentiable at $\mathrm{x}=0$ and $\mathrm{f}^{\prime}(0)=3$, then $\lim _{h \rightarrow 0} \frac{1}{h}(f(h)-1)$ is equal to $\_\_\_\_$ .
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