CARBONYL COMPOUNDS AND CARBOXYLIC ITS DERIVATIVES_JEE-Main_31-1-23{S1} - Competishun

JEE MAIN 2023

31-01-2023 S1

Question

Cobalt chloride when dissolved in water forms pink colored complex X which has octahedral geometry. This solution on treating with cone HC1 forms deep blue complex, Y which has a Z geometry. X, Y and Z, respectively, are

Select the correct option:

$\mathrm{X}=\left[\mathrm{Co}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+}, \mathrm{Y}=\left[\mathrm{CoCl}_4\right]^{2-}, \mathrm{Z}=$ Tetrahedral

$\mathrm{X}=\left[\mathrm{Co}\left(\mathrm{H}_2 \mathrm{O}_6\right)\right]^{2+}, \mathrm{Y}=\left[\mathrm{CoCl}_6\right]^{3-}, \mathrm{Z}=$ Octahedral

$\mathrm{X}=\left[\mathrm{Co}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{3+}, \mathrm{Y}=\left[\mathrm{CoCl}_6\right]^{3-}, \mathrm{Z}=$ Octahedral

$\mathrm{X}=\left[\mathrm{Co}\left(\mathrm{H}_2 \mathrm{O}\right)_4 \mathrm{Cl}_2\right]^{+}, \mathrm{Y}=\left[\mathrm{CoCl}_4\right]^{2-}, \mathrm{Z}=$ Tetrahedral

✓ Correct! Well done.

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Solution

Question Tags

JEE Main

Chemistry

Hard

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