Consider the following cell reaction:
$$
2 \mathrm{Fe}_{(\mathrm{s})}+\mathrm{O}_{2(\mathrm{~g})}+4 \mathrm{H}_{(\mathrm{aq})}^{+} \rightarrow 2 \mathrm{Fe}_{(\mathrm{aq})}^{2+}+2 \mathrm{H}_2 \mathrm{O}_{(f)} \mathrm{E}^{\circ}=1.67 \mathrm{~V}
$$
At $\left[\mathrm{Fe}^{2+}\right]=10^{-3} \mathrm{M}, \mathrm{P}\left(\mathrm{O}_2\right)=0.1 \mathrm{~atm}$ and $\mathrm{pH}=3$, the cell potential at $25^{\circ} \mathrm{C}$ is
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