Semiconductor Electronics_JEE-Main 08-4-2023_(S2) - Competishun

JEE MAIN 2023

8-4-2023 S2

Question

For a given transistor amplifier circuit in CE configuration $\mathrm{V}_{c c}=1 \mathrm{~V}, \mathrm{R}_{\mathrm{G}}=1 \mathrm{k} \Omega, \mathrm{R}_{\mathrm{b}}=100 \mathrm{k} \Omega$ and $\beta=$ 100 . Value of base current Ib is

Select the correct option:

$\mathrm{I}_{\Omega}=1.0 \mu \mathrm{~A}$

$\mathrm{I}_{\mathrm{k}}=0.10 \mu \mathrm{~A}$

$I_{\Omega}=100 \mu \mathrm{~A}$

$\mathrm{Id}_2=10 \mu \mathrm{~A}$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Question Tags

JEE Main

Physics

Medium

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