For reaction $\mathrm{A} \rightarrow \mathrm{P}$, rate constant $\mathrm{k}=1.5 \times 10^3 \mathrm{~s}^{-1}$ at $27^{\circ} \mathrm{C}$ If activation energy for the above reaction is $60 \mathrm{~kJ} \mathrm{~mol}^{-1}$, then the temperature (in ${ }^{\circ} \mathrm{C}$ ) at which rate constant, $\mathrm{k}=4.5 \times 10^3 \mathrm{~s}^{-1}$ is $\_\_\_\_$ . (Nearest integer) Given : $\log 2=0.30, \log 3=0.48, \mathrm{R}=8.3 \mathrm{~J} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}, \ln 10=2.3$