Moving galvanometer current |ChemistryEverydayLifeJEEMain2023

JEE MAIN 2023

10-4-2023

Question

Given below are two statement: Statement-wir if the number of turns in the coil of a moving coil galvanometer is doubled then the current sensitivity becomes double. Statement-II : Increasing current sensitivity of a moving coil galvanometer by only increasing the number of turns in the coil will also increase its voltage sensitivity in the same ratio: In the light of the above statement, choose the correct answer from the options given below:

Select the correct option:

Statement I is false but Statement II is true

Both Statement I and Statement II are true

Both Statement I and Statement II are false

Statement I is true but Statement II is false

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Sol. For a moving coil galvanometer $$ \begin{aligned} & \operatorname{BiNA}=k \theta \\ & \theta=\left(\frac{B N A}{k}\right) i ; \text { Current sensitive }=\frac{B N A}{k} \end{aligned} $$ So, if N is doubled then current sensitivity is doubled. Voltage sensitivity $B \frac{V}{R} N A=k \theta$ $\mathrm{V}=\frac{\mathrm{BNA}}{\mathrm{Rk}} \theta$, as N is doubled R is also doubled. So, no change in voltage sensitivity. Hence, option (4) is right.

Question Tags

JEE Main

Physics

Medium

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