Given below are two statements:
Statement (I): When an object is placed at the centre of curvature of a concave lens, image is formed at the centre of curvature of the lens on the other side.
Statement (II): Concave lens always forms a virtual and erect image.
In the light of the above statements, choose the correct answer from the options given below:
Select the correct option:
A
Statement I is false but Statement II is true.
B
Both Statement I and Statement II are false.
C
Statement I is true but Statement II is false.
D
Both Statement I and Statement II are true.
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
$$
\begin{aligned}
& \frac{1}{v}-\frac{1}{u}=\frac{1}{f} \\
& \frac{1}{v}-\frac{1}{-2 f}=\frac{1}{-f} \\
& \Rightarrow \frac{1}{v}=\frac{-1}{2 f} \Rightarrow v=-2 f \\
& \frac{1}{v}=\frac{1}{u}+\frac{1}{f} \Rightarrow \text { Virtual image of Real object. }
\end{aligned}
$$
In statement II, it is not mentioned that object is real or virtual hence Statement II is false.
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