Given $\frac{b+c}{11}=\frac{c+a}{12}=\frac{a+b}{13}$ for $\triangle A B C$ with usual natation. If $\frac{\cos A}{\alpha}=\frac{\cos B}{\beta}=\frac{\cos C}{12}$, then the ordered triplet $(\alpha$, $\beta, \gamma$ ) has a value
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