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JEE MAIN 2020
05-09-20 S2
Question
If $L=\sin ^2\left(\frac{\pi}{16}\right)-\sin ^2\left(\frac{\pi}{8}\right)$ and
$M=\cos ^2\left(\frac{\pi}{16}\right)-\sin ^2\left(\frac{\pi}{8}\right)$, then
Select the correct option:
A
$L=-\frac{1}{2 \sqrt{2}}+\frac{1}{2} \cos \frac{\pi}{8}$
B
$M=\frac{1}{2 \sqrt{2}}+\frac{1}{2} \cos \frac{\pi}{8}$
C
$M=\frac{1}{4 \sqrt{2}}+\frac{1}{4} \cos \frac{\pi}{8}$
D
$L=\frac{1}{4 \sqrt{2}}+\frac{1}{4} \cos \frac{\pi}{8}$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
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