If the distance between the plane, $23 x-10 y-2 z+ 48=0$ and the plane containing the lines
$$
\frac{x+1}{2}=\frac{y-3}{4}=\frac{z+1}{3}
$$
and
$\frac{x+3}{2}=\frac{y+2}{6}=\frac{z-1}{\lambda}(\lambda \in R) \quad$ is equal to $\frac{k}{\sqrt{633}}$, then k is equal to
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